8q^2-41q+5=0

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Solution for 8q^2-41q+5=0 equation:


Simplifying
8q2 + -41q + 5 = 0

Reorder the terms:
5 + -41q + 8q2 = 0

Solving
5 + -41q + 8q2 = 0

Solving for variable 'q'.

Factor a trinomial.
(1 + -8q)(5 + -1q) = 0

Subproblem 1

Set the factor '(1 + -8q)' equal to zero and attempt to solve: Simplifying 1 + -8q = 0 Solving 1 + -8q = 0 Move all terms containing q to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -8q = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -8q = 0 + -1 -8q = 0 + -1 Combine like terms: 0 + -1 = -1 -8q = -1 Divide each side by '-8'. q = 0.125 Simplifying q = 0.125

Subproblem 2

Set the factor '(5 + -1q)' equal to zero and attempt to solve: Simplifying 5 + -1q = 0 Solving 5 + -1q = 0 Move all terms containing q to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1q = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1q = 0 + -5 -1q = 0 + -5 Combine like terms: 0 + -5 = -5 -1q = -5 Divide each side by '-1'. q = 5 Simplifying q = 5

Solution

q = {0.125, 5}

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